fix: indenting

README.md

@@ -43,17 +43,23 @@ the input sequence.
 ## Encryption Process
 
 Let $P$ represent the plaintext composed of a sequence of characters:
+
 $$P = p_{1},p_{2},\ldots,p_{n}$$
 
 The ciphertext $C$ is produced by applying the reversal transformation:
-$$C = \text{ reverse}(P) = p_{n},p_{n - 1},\ldots,p_{1}$$ For example,
+
-if $P = \text{ sula}$, then: $$C = \text{ alus }$$
+$$C = \text{ reverse}(P) = p_{n},p_{n - 1},\ldots,p_{1}$$
+
+For example, if $P = \text{ sula}$, then:
+
+$$C = \text{ alus }$$
 
 ## Decryption Process
 
 Given that the reversal operation is an involution (its own inverse),
 the decryption process involves applying the same transformation. Let
 $C$ be the ciphertext; then the plaintext $P$ is recovered as:
+
 $$P = \text{ reverse}(C)$$
 
 # Implementation Considerations

main.typ

@@ -69,11 +69,15 @@ the decryption operation -- they both consist of reversing the input sequence.
 == Encryption Process
 
 Let $P$ represent the plaintext composed of a sequence of characters:
+
 $ P = p_1, p_2, ..., p_n $
 
 The ciphertext $C$ is produced by applying the reversal transformation:
+
 $ C = "reverse"(P) = p_n, p_(n-1), ..., p_1 $
+
 For example, if $P = "sula"$, then:
+
 $ C = "alus" $
 
 == Decryption Process
@@ -81,6 +85,7 @@ $ C = "alus" $
 Given that the reversal operation is an involution (its own inverse), the
 decryption process involves applying the same transformation.
 Let $C$ be the ciphertext; then the plaintext $P$ is recovered as:
+
 $ P = "reverse"(C) $
 
 = Implementation Considerations