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fixup! refactor: redraw images using fletcher

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Kristofers Solo 2025-06-15 02:43:09 +03:00
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@ -505,8 +505,8 @@ recognizability/recognizable).
Problēma $A$, kurai neviena no $A$, $overline(A)$ nav daļēji atrisināma?
- $"EQUIV"(M_1, M_2) = 1$, ja $forall x: M_1(x) = M_2(x)$.
- $overline("EQUIV")(M_1, M_2) = 1$, ja $exists x: M_1(x) != M_2(x)$.
- $equiv(M_1, M_2) = 1$, ja $forall x: M_1(x) = M_2(x)$.
- $overline(equiv)(M_1, M_2) = 1$, ja $exists x: M_1(x) != M_2(x)$.
= Nekustīgo punktu teorija